下图所示区域位于某大陆西岸，结合图中信息（虚线为等高线）回答下面小题。
(1)位于两条等高线之间的闭合区域，如果其值与两侧等高线中的较低值相等，则闭合区域内的海拔低于其等高线的值；如图，若c＝b，则d<b，即“小于小的”。
(2)位于两条等高线之间的闭合区域，如果其值与两侧等高线中的较高值相等，则闭合区域内的海拔高于其等高线的值。如图，若c＝a，则d>a，即“大于大的”。
![](http://user.ks5u.cn/html/2018-01-17/OPZTB-VJLgZVWe-201811714412.012.png"/></p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0">24. 关于图中河流的叙述，正确的是</p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0">A. 流向为先向北后向西北 B. 补给类型主要为高山冰雪融水补给</p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0">C. 汛期出现在冬季 D. 图中河段长度约为200KM</p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0">25. 图中甲和乙的数值可能是</p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0">A. 400m、650m B. 800m、350m C. 400m、550m D. 800m、650m</p></p> <br/>
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答案及解析:
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<b style="background-color: buttonface; padding: 5px 10px;">知识点：地理</b></p>
<p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0"><span style="color1:#000000; font-family:宋体; font-size:11pt">24. C 25. A</span></p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0"><span style="color1:#000000; font-family:宋体; font-size:11pt">24. </span><span style="color1:#000000; font-family:宋体; font-size:11pt">等高线凸出方向和河流流向相反，根据图中指向标可知，该河流先自西北流向东南，然后向南流</span><span style="color1:#000000; font-family:宋体; font-size:11pt">，A</span><span style="color1:#000000; font-family:宋体; font-size:11pt">错误。该地位于</span><span style="color1:#000000; font-family:宋体; font-size:11pt">30°N</span><span style="color1:#000000; font-family:宋体; font-size:11pt">以北大陆西岸，为地中海气候，且地势较低，河流主要补给来源为雨水补给，</span><span style="color1:#000000; font-family:宋体; font-size:11pt">B</span><span style="color1:#000000; font-family:宋体; font-size:11pt">错误。地中海气候夏季炎热干燥、冬季温和多雨，因此河流汛期出现在冬季</span><span style="color1:#000000; font-family:宋体; font-size:11pt">，C</span><span style="color1:#000000; font-family:宋体; font-size:11pt">正确</span><span style="color1:#000000; font-family:宋体; font-size:11pt">。</span><span style="color1:#000000; font-family:宋体; font-size:11pt">根据图中比例尺和河流的图上长度，可推测该段河流的实际长度约为</span><span style="color1:#000000; font-family:宋体; font-size:11pt">120km，D</span><span style="color1:#000000; font-family:宋体; font-size:11pt">错误。</span></p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0"><span style="color1:#000000; font-family:宋体; font-size:11pt">25. </span><span style="color1:#000000; font-family:宋体; font-size:11pt">根据河流流向可知，图中甲线数值小于</span><span style="color1:#000000; font-family:宋体; font-size:11pt">600m</span><span style="color1:#000000; font-family:宋体; font-size:11pt">，又因为图中相邻等高线的差值是</span><span style="color1:#000000; font-family:宋体; font-size:11pt">200m，</span><span style="color1:#000000; font-family:宋体; font-size:11pt">所以甲的数值是</span><span style="color1:#000000; font-family:宋体; font-size:11pt">400m。</span><span style="color1:#000000; font-family:宋体; font-size:11pt">乙处数值符合“大于大值或小于小值”的规律，其外围等高线数值为</span><span style="color1:#000000; font-family:宋体; font-size:11pt">400m</span><span style="color1:#000000; font-family:宋体; font-size:11pt">，因此乙处数值范围是</span><span style="color1:#000000; font-family:宋体; font-size:11pt">（200m，400m）。</span><span style="color1:#000000; font-family:宋体; font-size:11pt">故选</span><span style="color1:#000000; font-family:宋体; font-size:11pt">A。</span></p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0"><span style="color1:#000000; font-family:宋体; font-size:11pt">【点睛】</span></p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; widows:0"><span style="color1:#000000; font-family:宋体; font-size:11pt">闭合等高线区域内海拔的计算</span><span style="color1:#000000; font-family:宋体; font-size:11pt">(</span><span style="color1:#000000; font-family:宋体; font-size:11pt">图中</span><span style="color1:#000000; font-family:宋体; font-size:11pt">a>b)</span></p><p style="font-size:11pt; line-height:150%; margin:0pt; orphans:0; text-align:center; widows:0"><img border=)